管理經濟學 - 經濟
By Linda
at 2008-10-01T01:10
at 2008-10-01T01:10
Table of Contents
※ 引述《btozoxo (阿賢)》之銘言：
: 題目:
: TR=1800Q-0.006Q^2
: MR=1800-0.012Q
: TC=12100000+800Q+0.004Q^2
: MC=800+0.008Q
: A. Calculate profit at the average cost minimizing activity level.
: B. ........................profit-maximizing activity level.
: C. Compare and discuss your answers to parts A and B.
: 我的想法:
: A. MC=AC → Q=55000 → πa=TR-TC=48950000
: B. MC=MR → Q=50000 → πb=TR-TC=12900000
: C. πa > πb? 利潤最大的狀況下之利潤，有可能小於平均成本最小時的利潤嗎?
A.
TR=1800*55000-0.006*(55000^2)
=99000000 -0.006*3025000000
=99000000 -18150000
=80850000
TC=1210000+800*55000+0.004*(55000^2)
=1210000+44000000 +0.004*3025000000
=1210000+44000000 +12100000
=68200000
TR-TC=80850000-68200000=12650000==\==48950000
--
: 題目:
: TR=1800Q-0.006Q^2
: MR=1800-0.012Q
: TC=12100000+800Q+0.004Q^2
: MC=800+0.008Q
: A. Calculate profit at the average cost minimizing activity level.
: B. ........................profit-maximizing activity level.
: C. Compare and discuss your answers to parts A and B.
: 我的想法:
: A. MC=AC → Q=55000 → πa=TR-TC=48950000
: B. MC=MR → Q=50000 → πb=TR-TC=12900000
: C. πa > πb? 利潤最大的狀況下之利潤，有可能小於平均成本最小時的利潤嗎?
A.
TR=1800*55000-0.006*(55000^2)
=99000000 -0.006*3025000000
=99000000 -18150000
=80850000
TC=1210000+800*55000+0.004*(55000^2)
=1210000+44000000 +0.004*3025000000
=1210000+44000000 +12100000
=68200000
TR-TC=80850000-68200000=12650000==\==48950000
--
Tags:
經濟
All Comments
By Skylar Davis
at 2008-10-01T14:54
at 2008-10-01T14:54
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