非符合homothetic的效用函數 - 經濟
By Elizabeth
at 2013-07-17T22:20
at 2013-07-17T22:20
Table of Contents
來源: 95台大經濟
科目:個體經濟學
問題:Which of the following utility functions defined on x1>0 and
x2>0 are (is ) not homothetic? (複選)
(a) 1/3ln(x1)+2/3ln(x2) (b) x1^1/3 * x2^2/3
(c) x1^1/3 + x2^2/3 (d) x1^1/4 * x2^1/2 + x1^1/2 * x2
(e) x1^1/3 * x2^2/3 + x1^1/2 * x2^1/2
我的想法:
按照我手上書的講法,將一個齊次函數做單調遞增轉換,即為一個齊序函數。
V=F[U(X,Y)] ,對V偏微U會大於0,則V為齊序函數。
那麼我將轉換函數定義為 V= U(X,Y) + C , C為大於零的常數 ,套上去
似乎全部都符合阿,為何答案給 (C) 為非齊序呢? 感謝各位
--
科目:個體經濟學
問題:Which of the following utility functions defined on x1>0 and
x2>0 are (is ) not homothetic? (複選)
(a) 1/3ln(x1)+2/3ln(x2) (b) x1^1/3 * x2^2/3
(c) x1^1/3 + x2^2/3 (d) x1^1/4 * x2^1/2 + x1^1/2 * x2
(e) x1^1/3 * x2^2/3 + x1^1/2 * x2^1/2
我的想法:
按照我手上書的講法,將一個齊次函數做單調遞增轉換,即為一個齊序函數。
V=F[U(X,Y)] ,對V偏微U會大於0,則V為齊序函數。
那麼我將轉換函數定義為 V= U(X,Y) + C , C為大於零的常數 ,套上去
似乎全部都符合阿,為何答案給 (C) 為非齊序呢? 感謝各位
--
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