關於平均成本&邊際成本 - 經濟

By Olive
at 2007-12-19T19:39
at 2007-12-19T19:39
Table of Contents
: APL = Q / L MPL = dQ / dL
: 當APL最大時 MPL = dQ / dL = Q / L = APL
: --> dAPL / dL = [dQ / dL - Q / L] * 1 / L = 0
: -----------------------------------End--------------------------------------
: 想請問各位為什麼 dAPL / dL 會等於 [ MPL - APL ] * 1 / L
: 然後在我自己的濫數學計算中
: dAPL / dL = ( dQ / dL ) / dL
: 要怎麼用才會變成 [dQ / dL - Q / L] * 1 / L 哩 @@
: 麻煩各位了這邊卡住好久啊= ="
我就把勞動的代號省略囉
dAP/dL = d( Q/L ) / dL ----> AP = Q/L
= ( dQ/dL * L - Q * dL/dL ) / L^2 ----> 微分的除法
= ( MP * L - Q ) / L^2 ----> dQ/dL = MP , dL/dL = 1
= ( MP * L ) / L^2 - Q / L^2
= MP/L - AP/L
= ( MP - AP ) / L #
==
dQ / dL = MP , Q / L = AP 瞧瞧上式 其實都只是微分的推導跟APMP的換算
--
: 當APL最大時 MPL = dQ / dL = Q / L = APL
: --> dAPL / dL = [dQ / dL - Q / L] * 1 / L = 0
: -----------------------------------End--------------------------------------
: 想請問各位為什麼 dAPL / dL 會等於 [ MPL - APL ] * 1 / L
: 然後在我自己的濫數學計算中
: dAPL / dL = ( dQ / dL ) / dL
: 要怎麼用才會變成 [dQ / dL - Q / L] * 1 / L 哩 @@
: 麻煩各位了這邊卡住好久啊= ="
我就把勞動的代號省略囉
dAP/dL = d( Q/L ) / dL ----> AP = Q/L
= ( dQ/dL * L - Q * dL/dL ) / L^2 ----> 微分的除法
= ( MP * L - Q ) / L^2 ----> dQ/dL = MP , dL/dL = 1
= ( MP * L ) / L^2 - Q / L^2
= MP/L - AP/L
= ( MP - AP ) / L #
==
dQ / dL = MP , Q / L = AP 瞧瞧上式 其實都只是微分的推導跟APMP的換算
--
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By Bethany
at 2007-12-23T16:28
at 2007-12-23T16:28

By Tom
at 2007-12-26T23:50
at 2007-12-26T23:50
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