文義讀取 or 均等 - 專利
By Cara
at 2016-05-04T19:29
at 2016-05-04T19:29
Table of Contents
不好意思 外行觀念不清楚
今天有個物品甲 是A+(B+C+D)
其中B.D是裝在C之上
連接順序是ACBCD
另外有個物品乙 A+(B+C')+(C+D)
C'跟C是同樣東西
B裝在C'上,D裝在C上
連接順序是AC'BCD
物品乙就是把物品甲其中一部分(B+C')
拆出來另外放而已
請問這樣要看做文義讀取 還是均等呢?
補充:
甲:
外部電源-電線-電路板-電路1-電路板-電路2
(電路1.2都在一塊電路板)
乙
外部電源-電線-電路板1-電路1-電線-電路板2-電路2
(電路1.2分別在兩塊電路板)
補充2:
再連接至電路板上設一電源電路(電路1),使其輸入電源轉換為直流電源電路,
以提供符合電路2之電源並讓電路2使用
--
今天有個物品甲 是A+(B+C+D)
其中B.D是裝在C之上
連接順序是ACBCD
另外有個物品乙 A+(B+C')+(C+D)
C'跟C是同樣東西
B裝在C'上,D裝在C上
連接順序是AC'BCD
物品乙就是把物品甲其中一部分(B+C')
拆出來另外放而已
請問這樣要看做文義讀取 還是均等呢?
補充:
甲:
外部電源-電線-電路板-電路1-電路板-電路2
(電路1.2都在一塊電路板)
乙
外部電源-電線-電路板1-電路1-電線-電路板2-電路2
(電路1.2分別在兩塊電路板)
補充2:
再連接至電路板上設一電源電路(電路1),使其輸入電源轉換為直流電源電路,
以提供符合電路2之電源並讓電路2使用
--
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專利
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